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McGraw-Hill My Math Grade 4 Volume 1
Textbook: mcgraw-hill my math grade 4 volume 1 isbn: 9780021150236.
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Chapter 1: Place Value
Lesson 1: place value, lesson 2: read and write multi-digit numbers, lesson 3: compare numbers, lesson 4: order numbers, lesson 5: use place value to round, chapter 2: add and subtract whole numbers, lesson 1: addition properties and subtraction rules, lesson 2: addition and subtraction patterns, lesson 3: add and subtract mentally, lesson 4: estimate sums and difference, lesson 5: add whole numbers, lesson 6: subtract whole numbers, lesson 7: subtract across zeros, lesson 8: solve multi-step word problems, chapter 3: understand multiplication and division, lesson 1: relate multiplication and division, lesson 2: relate division and subtraction, lesson 3: multiplication as comparison, lesson 4: compare to solve problems, lesson 5: multiplication properties and division rules, lesson 6: the associative property of multiplication, lesson 7: factors and multiples, chapter 4: multiply with one-digit numbers, lesson 1: multiples of 10, 100, and 1,000, lesson 2: round to estimate products, lesson 3: hands on: use place value to multiply, lesson 4: hands on: use models to multiply, lesson 5: multiply by a two-digit number, lesson 6: hands on: model regrouping, lesson 7: the distributive property, lesson 8: multiply with regrouping, lesson 9: multiply by a multi-digit number, lesson 10: multiply across zeros, chapter 5: multiply with two-digit numbers, lesson 1: multiply by tens, lesson 2: estimate products, lesson 3: hands on: use the distributive property to multiply, lesson 4: multiply by a two-digit number, lesson 5: solve multi-step word problems, chapter 6: divide by a one-digit number, lesson 1: divide multiples of 10, 100, and 1,000, lesson 2: estimate quotients, lesson 3: hands on: use place value to divide, lesson 4: divide with remainders, lesson 5: interpret remainders, lesson 6: place the first digit, lesson 7: hands on: distributive property and partial quotients, lesson 8: divide greater numbers, lesson 9: quotients with zeros, lesson 10: solve multi-step word problems, chapter 7: patterns and sequences, lesson 1: nonnumeric patterns, lesson 2: numeric patterns, lesson 3: sequences, lesson 4: addition and subtraction rules, lesson 5: multiplication and division rules, lesson 6: order of operations, lesson 7: hands on: equations with two operations, lesson 8: equations with multiple operations.
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McGraw Hill My Math Grade 4 Chapter 9 Lesson 6 Answer Key Add Mixed Numbers
All the solutions provided in McGraw Hill My Math Grade 4 Answer Key PDF Chapter 9 Lesson 6 Add Mixed Numbers will give you a clear idea of the concepts.
McGraw-Hill My Math Grade 4 Answer Key Chapter 9 Lesson 6 Add Mixed Numbers
Mixed numbers are numbers with a whole number and a fraction. You can decompose mixed numbers to add them. Use the Associative Property to group the whole numbers and like fractions together.
Explanation: Number of cups of strawberries she used = 3\(\frac{1}{4}\) Number of cups of blueberries she used = 2\(\frac{1}{4}\) Number of cups of berries did Madison use altogether = Number of cups of strawberries she used + Number of cups of blueberries she used = 3\(\frac{1}{4}\) + 2\(\frac{1}{4}\) = {[(3 × 4) + 1] ÷ 4} + {[(2 × 4) + 1] ÷ 4} = [(12 + 1) ÷ 4] + [(8 + 1) ÷ 4] = \(\frac{13}{4}\) + \(\frac{9}{4}\) = (13 + 9) ÷ 4 = \(\frac{22}{4}\) ÷ \(\frac{2}{2}\) = \(\frac{11}{2}\) or 5\(\frac{1}{2}\)
Explanation: Sum of mixed fractions: 1\(\frac{1}{3}\) + 2\(\frac{1}{3}\) = {[(1 × 3) + 1] ÷ 3} + {[(2 × 3) + 1] ÷ 3} = [(3 + 1) ÷ 3] + [(6 + 1) ÷ 3] = \(\frac{4}{3}\) + \(\frac{7}{3}\) = [(4 + 7) ÷ 3] = \(\frac{11}{3}\) or 3\(\frac{2}{3}\)
Explanation: A mixed number is a whole number, and a proper fraction represented together. It generally represents a number between any two whole numbers. The numbers that include natural numbers and zero are called whole numbers.
Explanation: 2\(\frac{3}{6}\) = 1 + 1 + \(\frac{3}{6}\) 2\(\frac{1}{6}\) = 1 + 1 + \(\frac{1}{6}\) Sum of 2\(\frac{3}{6}\) and 2\(\frac{1}{6}\) = 1 + 1 + \(\frac{3}{6}\) + 1 + 1 + \(\frac{1}{6}\) = 4 + \(\frac{3}{6}\) + \(\frac{1}{6}\) = 4 + [(3 + 1) ÷ 6] = 4 + \(\frac{4}{6}\) = 4\(\frac{4}{6}\)
McGraw Hill My Math Grade 4 Chapter 9 Lesson 6 My Homework Answer Key
Practice Find each sum. Write in simplest form. Question 1. 4\(\frac{1}{4}\) + 2\(\frac{2}{4}\) = _______________ Answer: Sum of 4\(\frac{1}{4}\) and 2\(\frac{2}{4}\), we get \(\frac{27}{4}\) or 6\(\frac{3}{4}\)
Explanation: Sum: 4\(\frac{1}{4}\) + 2\(\frac{2}{4}\) = {[(4 × 4) + 1] ÷ 4} + {[(2 × 4) + 2] ÷ 4} = [(16 + 1) ÷ 4] + [(8 + 2) ÷ 4] = (17 ÷ 4) + (10 ÷ 4) = (17 + 10) ÷ 4 = \(\frac{27}{4}\) or 6\(\frac{3}{4}\)
Question 2. 3\(\frac{3}{6}\) + 6\(\frac{1}{6}\) = ________________ Answer: Sum of 3\(\frac{3}{6}\) and 6\(\frac{1}{6}\), we get \(\frac{29}{3}\) or 9\(\frac{2}{6}\)
Explanation: Sum of 3\(\frac{3}{6}\) + 6\(\frac{1}{6}\): 3\(\frac{3}{6}\) + 6\(\frac{1}{6}\) = {[(3 × 6) + 3] ÷ 6} + {[(6 × 6) + 1] ÷ 6} = [(18 + 3) ÷ 6] + [(36 + 1) ÷ 6] = \(\frac{21}{6}\) + \(\frac{37}{6}\) = [(21 + 37) ÷ 6] = \(\frac{58}{6}\) ÷ \(\frac{2}{2}\) = \(\frac{29}{3}\) or 9\(\frac{2}{6}\)
Question 3. 6\(\frac{2}{5}\) + 3\(\frac{2}{5}\) = ________________ Answer: Sum of 6\(\frac{2}{5}\) and 3\(\frac{2}{5}\), we get \(\frac{49}{5}\) or 9\(\frac{4}{5}\)
Explanation: Sum: 6\(\frac{2}{5}\) + 3\(\frac{2}{5}\) = {[(6 × 5) + 2] ÷ 5} + {[(3 × 5) + 2] ÷ 5} = [(30 + 2) ÷ 5] + [(15 + 2) ÷ 5] = \(\frac{32}{5}\) + \(\frac{17}{5}\) = [(32 + 17) ÷ 5] = \(\frac{49}{5}\) or 9\(\frac{4}{5}\)
Question 4. 4\(\frac{1}{6}\) + 1\(\frac{2}{6}\) = ________________ Answer: Sum of 4\(\frac{1}{6}\) and 1\(\frac{2}{6}\), we get \(\frac{17}{3}\) or 5\(\frac{2}{3}\)
Explanation: Sum: 4\(\frac{1}{6}\) + 1\(\frac{2}{6}\) = {[(4 × 6) + 1] ÷ 6} + {[(1 × 6) + 2] ÷ 6} = [(24 + 1) ÷ 6] + [(7 + 2) ÷ 6] = \(\frac{25}{6}\) + \(\frac{9}{6}\) = [(25 + 9) ÷ 6] = \(\frac{34}{6}\) ÷ \(\frac{2}{2}\) = \(\frac{17}{3}\) or 5\(\frac{2}{3}\)
Question 5. 2\(\frac{1}{4}\) + 9\(\frac{1}{4}\) = ________________ Answer: Sum of 2\(\frac{1}{4}\) and 9\(\frac{1}{4}\), we get \(\frac{23}{2}\) or 11\(\frac{1}{2}\)
Explanation: Sum: 2\(\frac{1}{4}\) + 9\(\frac{1}{4}\) = {[(2 × 4) + 1] ÷ 4} + {[(9 × 4) + 1] ÷ 4} = [(8 + 1) ÷ 4] + [(36 + 1) ÷ 4] = \(\frac{9}{4}\) + \(\frac{37}{4}\) = [(9 + 37) ÷ 4] = \(\frac{46}{4}\) ÷ \(\frac{2}{2}\) = \(\frac{23}{2}\) or 11\(\frac{1}{2}\)
Question 6. 7\(\frac{4}{8}\) + 1\(\frac{3}{8}\) = _________________ Answer: Sum of 7\(\frac{4}{8}\) and 1\(\frac{3}{8}\), we get \(\frac{71}{8}\) or 8\(\frac{7}{8}\)
Explanation: Sum: 7\(\frac{4}{8}\) + 1\(\frac{3}{8}\) = {[(7 × 8) + 4] ÷ 8} + {[(1 × 8) + 3] ÷ 8} = [(56 + 4) ÷ 8] + [(8 + 3) ÷ 8] = \(\frac{60}{8}\) + \(\frac{11}{8}\) = [(60 + 11) ÷ 8] = \(\frac{71}{8}\) or 8\(\frac{7}{8}\)
Question 7. 5\(\frac{6}{10}\) + 8\(\frac{3}{10}\) = ________________ Answer: Sum of 5\(\frac{6}{10}\) and 8\(\frac{3}{10}\), we get \(\frac{139}{10}\) or 13\(\frac{9}{10}\)
Explanation: Sum: 5\(\frac{6}{10}\) + 8\(\frac{3}{10}\) = {[(5 × 10) + 6] ÷ 10} + {[(8 × 10) + 3] ÷ 10} = [(50 + 6) ÷ 10] + [(80 + 3) ÷ 10] = \(\frac{56}{10}\) + \(\frac{83}{10}\) = [(56 + 83) ÷ 10] = \(\frac{139}{10}\) or 13\(\frac{9}{10}\)
Question 8. 12\(\frac{5}{10}\) + 6\(\frac{1}{10}\) = __________________ Answer: Sum of 12\(\frac{5}{10}\) and 6\(\frac{1}{10}\), we get \(\frac{93}{5}\) or 18\(\frac{3}{10}\)
Explanation: Sum: 12\(\frac{5}{10}\) + 6\(\frac{1}{10}\) = {[(12 × 10) + 5] ÷ 10} + {[(6 × 10) + 1] ÷ 10} = [(120 + 5) ÷ 10] + [(60 + 1) ÷ 10] = \(\frac{125}{10}\) + \(\frac{61}{10}\) = [(125 + 61) ÷ 10] = \(\frac{186}{10}\) ÷ \(\frac{2}{2}\) = \(\frac{93}{5}\) or 18\(\frac{3}{10}\)
Problem Solving Solve. Write the answer in simplest form. Question 9. James cut 1\(\frac{1}{4}\) dozen flowers for a bouquet. Gwen added 1\(\frac{2}{4}\) dozen flowers to the bouquet. How many dozen flowers are there altogether? Answer: Number of dozen flowers are there altogether = \(\frac{11}{4}\)
Explanation: Number of dozen flowers for a bouquet James cut = 1\(\frac{1}{4}\) Number of dozen flowers for a bouquet Gwen added = 1\(\frac{2}{4}\) Number of dozen flowers are there altogether = Number of dozen flowers for a bouquet James cut + Number of dozen flowers for a bouquet Gwen added = 1\(\frac{1}{4}\) + 1\(\frac{2}{4}\) = {[(1 × 4) + 1] ÷ 4} + {[(1 × 4) + 2] ÷ 4} = [(4 + 1) ÷ 4] + [(4 + 2) ÷ 4] = \(\frac{5}{4}\) + \(\frac{6}{4}\) = (5 + 6) ÷ 4 = \(\frac{11}{4}\)
Question 10. On Monday, Simon’s class filled 3\(\frac{2}{5}\) boxes with books to donate to charity. On Wednesday, the class filled 4\(\frac{2}{5}\) more boxes with books to donate. How many boxes of books will Simon’s class donate in all? Answer: Number of boxes of books Simon’s class donate in all = \(\frac{39}{5}\)
Explanation: Number of boxes with books to donate to charity Simon’s class filled On Monday = 3\(\frac{2}{5}\) Number of more boxes with books to donate to charity Simon’s class filled On Wednesday = 4\(\frac{2}{5}\) Number of boxes of books Simon’s class donate in all = Number of more boxes with books to donate to charity Simon’s class filled On Wednesday + Number of boxes with books to donate to charity Simon’s class filled = 4\(\frac{2}{5}\) – 3\(\frac{2}{5}\) = {[(4 × 5) + 2] ÷ 5} + {[(3 × 5) + 2] ÷ 5} = [(20 + 2) ÷ 5] + [(15 + 2) ÷ 5] = (22 ÷ 5) + (17 ÷ 5) = (22 + 17) ÷ 5 = \(\frac{39}{5}\)
Question 11. Mathematical PRACTICE Use Number Sense Marissa rode her bike to the park and back home. She lives 2\(\frac{3}{10}\) miles from the park. How many miles did Marissa ride her bike in all? Answer: Number of miles Marissa ride her bike in all = \(\frac{23}{5}\)
Explanation: Number of miles from the park she lives = 2\(\frac{3}{10}\) Marissa rode her bike to the park and back home. => Number of miles Marissa ride her bike in all = 2 × Number of miles from the park she lives => 2 × 2\(\frac{3}{10}\) => 2 × {[(2 × 10) + 3] ÷ 10} => 2 × \(\frac{23}{10}\) => 1 × \(\frac{23}{5}\) => \(\frac{23}{5}\)
Test Practice Question 12. Nate is 10\(\frac{9}{12}\) years old. How old will he be in 2\(\frac{1}{12}\) more years? (A) 13\(\frac{1}{3}\) years old (B) 12\(\frac{5}{6}\) years old (C) 12\(\frac{1}{4}\) years old (D) 12\(\frac{3}{12}\) years old Answer: Future age of Nate = 12\(\frac{5}{6}\) years old. (B) 12\(\frac{5}{6}\) years old
Explanation: Present age of Nate = 10\(\frac{9}{12}\) years. Future age of Nate = 2\(\frac{1}{12}\) + Present age of Nate = 2\(\frac{1}{12}\) + 10\(\frac{9}{12}\) = {[(2 × 12) + 1] ÷ 12} + {[(10 × 12) + 9] ÷ 12} = [(24 + 1) ÷ 12] + [(120 + 9) ÷ 12] = (25 ÷ 12) + (129 ÷ 12) = (25 + 129) ÷ 12 = 154 ÷ 12 = \(\frac{154}{12}\) ÷ \(\frac{2}{2}\) = \(\frac{77}{6}\) = 12\(\frac{5}{6}\) years.
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My Homework Homework Helper Need help? connectED.mcgraw-hill.com Rewrite to subtract 82 - 49. 12 8 2-4 9 3 3 7 eHelp c Rewrite Two-Digit Subtraction My Homework Lesson 6 Practice Rewrite the problems. Subtract. 1. 74 - 25 - 2. 60 - 37 - 3. 86 - 48 - 4. 45 - 28 5. 84 - 38 6. 37 18 Helpful Hint When you subtract, always put the larger ...
Lesson 6 Divide by 8 and 9 Practice Use counters to find the number of equal groups or the number in each group. 1. 27 counters 9 equal groups in each group So, 27 ÷ 9 = ÷ . 2. 54 counters ... Lesson 6 My Homework 465 eHelp Operations and Algebraic Thinking 3.OA.2, 3.OA.3, 3.OA.4, 3.OA.6
McGraw Hill My Math Grade 5 Chapter 6 Lesson 6 My Homework Answer Key. Practice. Multiply. Question 1. 0.13 × 10 = _____ Answer: 1.3 Explanation: To multiply a decimal by a power of ten, move the decimal point to the right the same number of zeros in the power of ten. This is also the same number as the exponent on 10. 0.13 × 10 = 1.3 ...
Place Value Through ThousandthsWord forms and expanded forms of decimalsemail: [email protected]
Lesson 6 Name My Homework Time to the Hour: Digital Practice Tell what time is shown. Write the time on the digital clock. 1. 12 1 6 5 3 2 9 8 7 10 11 2. 12 1 6 5 3 2 9 8 7 10 11 Homework Helper Need help? connectED.mcgraw-hill.com An analog clock uses an hour hand and a minute hand to show time. A digital clock uses numbers to
McGraw-Hill My Math Grade 3 Answer Key Chapter 2 Lesson 6 Use Models to Add. Use a place-value chart and base-ten blocks to model three-digit addition with regrouping. To regroup means to rename a number using place value. Build It. While on a trip, Rosa counted 148 red cars and 153 green cars. How many total cars did Rosa count? Find 148 + 153.
Compare Fractions in easy way
McGraw Hill MyMath - Fourth Grade - Chapter 8: Lesson 6 - Compare and Order Fractions
The McGraw-Hill My Math Learning Solution provides an easy and flexible way to diagnose and fill gaps in understanding so that all students can meet grade-level expectations - and accelerate beyond: . Strong, equitable core instruction with actionable data Best-in-class resources and targeted instructional strategies Personalized, student-driven learning
Lesson 6 Problem Solving: Use Models $4 Program: GMH CCM Component: SE PDF Pass Vendor: Quad Graphics Grade: 3 Lesson 6 My Homework 281 eHelp Operations and Algebraic Thinking 3.OA.4, 3.OA.7 00281_0282_Gr3_S_C05L6HW_115022.indd 281281_0282_Gr3_S_C05L6HW_115022.indd 281 88/22/11 1:05 PM/22/11 1:05 PM.
Homework Helper Need help? connectED.mcgraw-hill.com Add Mixed Numbers Find each sum. Write in simplest form. 1. 4 1 _ 4 + 2 2 _ 4 = 2. 3 3 _ 6 + 6 1 _ 6 = Gavin put 2 __1 3 scoops of chili in his bowl. He put 4 1 __ 3 scoops of chili in his dad's bowl. How many scoops of chili do Gavin and his dad have in all? Find 2 1 _ 3 + 4 1 _ . 3
Lesson 6 Multiply Fractions Practice Multiply. Write in simplest form. 1. _4 9 ... Lesson 6 My Homework 743 Number and Operations — Fractions 5.NF.4, 5.NF.4a, 5.NF.4b, 5.NF.5, 5.NF.5b, 5.NF.6 00743_0744_Gr5_S_C10L6HW_116196.indd 743743_0744_Gr5_S_C10L6HW_116196.indd 743 5/27/11 5/27/11 1:06 PM 1:06 PM.
All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 8 Lesson 6 Compare Fractions will give you a clear idea of the concepts.. McGraw-Hill My Math Grade 5 Answer Key Chapter 8 Lesson 6 Compare Fractions. Math in My World. Example 1 Trevor made 2 out of 3 goals and Tyler made 5 out of 6.
Lesson 6 Draw Angles Practice Draw an angle for each measure. 1. 65° 2. 140° Homework Helper Draw a 40° angle. Classify it as acute, right, or obtuse. Draw one ray of the angle. Mark the endpoint and draw a ray. Measure the angle. Place the protractor along the ray as you would to measure an angle. On the protractor, find 40°, and make a ...
Investigate patterns in vertical and horizontal lines, interpret the points on the plane as distances from the axes, help teachers, help students, help paren...
Textbook: McGraw-Hill My Math Grade 4 Volume 1ISBN: 9780021150236. Use the table below to find videos, mobile apps, worksheets and lessons that supplement McGraw-Hill My Math Grade 4 Volume 1 book.
Lesson 6 Equivalent Fractions Practice Complete each number sentence to show equivalent fractions. 1. 2. _1 = 4 = _ 8 _ 6 _ 3 Homework Helper Marley packed 2 of the 4 apricots her mom just bought for her lunch. Find an equivalent fraction to represent the part of the apricots that Marley just packed. Represent the fraction on a number line.
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Lesson Check (CC.5.NF.l) 1. Ming has a goal to jog 4Ž miles each day. On Monday she jogged 52 miles. By how much 16 did she exceed her goal for that day? IL miles 16 @ IL miles 16 IL miles 16 IL miles 14 2. STEST At the deli, Ricardo ordered 35 pounds of cheddar cheese and 2a pounds of mozzarella cheese.
All the solutions provided in McGraw Hill My Math Grade 3 Answer Key PDF Chapter 12 Lesson 6 Measure to Halves and Fourths of an Inch will give you a clear idea of the concepts. McGraw-Hill My Math Grade 3 Answer Key Chapter 12 Lesson 6 Measure to Halves and Fourths of an Inch. One-half inch (\(\frac{1}{2}\)) is one of two equal parts of one inch.
All the solutions provided in McGraw Hill Math Grade 4 Answer Key PDF Chapter 6 Lesson 6 Interpret Remainders will give you a clear idea of the concepts.. McGraw-Hill My Math Grade 4 Answer Key Chapter 6 Lesson 6 Interpret Remainders. Math in My World. Example 1 Mandy wants to buy 4 books that each cost the same amount.
Find 3 14 + 2 14. Decompose each mixed number as a sum of whole numbers and unit fractions. So, Madison used cups of berries. Answer: Number of cups of berries did Madison use altogether = 112 or. Explanation: Number of cups of strawberries she used = 3 14. Number of cups of blueberries she used = 2 14.
Lesson 6 Use Multiplication to Find Combinations yellow heart yellow, heart star yellow, star square yellow, square ... square heart blue star 23 6× = combinations Program: GMH CCM Component: SE PDF Pass Vendor: Quad Graphics Grade: 3 Lesson 6 My Homework 229 Operations and Algebraic Thinking 3.OA.1, 3.OA.3, 3.OA.8 eHelp 0229_0230_Gr3_S ...