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Eureka Math Grade 4 Module 2 Lesson 2 Answer Key

Engage ny eureka math 4th grade module 2 lesson 2 answer key, eureka math grade 4 module 2 lesson 2 problem set answer key.

Question 1. Complete the conversion table.

Explanation: Converted the conversion table as shown above as We know 1 kg = 10 3 or 1000 g, So 1 kg = 1,000 g.

3 kg = 3,000 g as 3 kg = 3 X 10 3 g = 3 X 1000g = 3,000 g.

4 kg = 4,000 g as 4 kg = 4 X 10 3 g = 4 X 1000 = 4,000 g.

17000 g = 17,000 ÷ 10 3 kg = 17 kg, So 17 kg = 17,000 g.

20 kg = 20,000 g as 20 kg = 20 X 10 3 g = 20 X 1000 = 20,000 g

300 kg = 300,000 g as 300 kg = 300 X 10 3 g =  300 X 1000 = 300,000 g.

Question 2. Convert the measurements. a. 1 kg 500 g = ______1500___ g b. 3 kg 715 g = _____3715____ g c. 17 kg 84 g = _____17,084___ g d. 25 kg 9 g = _____25,009___ g e. __7___ kg __481__ g = 7,481 g f. 210 kg 90 g = ___210,090___ g

a. 1 kg 500 g = 1500 g

Explanation: 1 kg 500 g  as 1 kg = 10 3 g= 1000 g, 1 X 1000 g + 500 g= 1500 g.

b. 3 kg 715 g = 3715 g,

Explanation: 3 kg 715 g  as 1 kg = 10 3 g= 1000 g, 3 X 1000 g + 715  g = 3000 g + 715 g= 3715 g.

c. 17 kg 84 g = 17,084 g,

Explanation: 17 kg 84 g  as 1 kg = 10 3 g= 1000 g, 17 X 1000 g+ 84 g= 17000 g + 84 g= 17,084 g.

d. 25 kg 9 g = 25,009 g,

Explanation: 25 kg 9 g  as 1 kg = 10 3 g= 1000 g, 25 X 1000 g + 9 g = 25000 g + 9 g = 25,009 g.

e. 7,481 g = 7 kg 481 g,

Explanation: As 1000 g = 1 kg, So 7481 g = 7481 kg ÷ 1000 g= 7 kg 481 g.

f. 210 kg 90 g = 210,090 g,

Explanation: 210 kg 90 g  as 1 kg = 10 3 g= 1000 g, 210 X 1000 g + 90 g = 210000 g + 90 g = 210,090 g.

Question 3. Solve. a. 3,715 g – 1,500 g b. 1 kg – 237 g c. Express the answer in the smaller unit: 25 kg 9 g + 24 kg 991 g d. Express the answer in the smaller unit: 27 kg 650 g – 20 kg 990 g e. Express the answer in mixed units: 14 kg 505 g – 4,288 g f. Express the answer in mixed units: 5 kg 658 g + 57,481 g

Use a tape diagram to model each problem. Solve using a simplifying strategy or an algorithm, and write your answer as a statement.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-1

Explanation: Given  3,715 g – 1,500 g = 3715 g -1500 g 2,215  g Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement three thousand seven hundred fifteen grams minus  fifteen hundred grams is equal to two thousand and two hundred fifteen grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-2

Explanation: Given  1 kg – 237 g = As 1 kg = 1 X 1000 g = 1000 g – 237 g = 1000 g – 237 g 763 g Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement one thousand grams minus two hundred thirty seven grams is equal to seven hundred sixty three grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-3

Explanation: Given  25 kg 9 g + 24 kg 991 g = As 25 kg 9 g = 25 X 1000 g + 9 g = 25000 g + 9 g = 25009 g, 24 kg 991 g = 24 X 1000 g + 991 g = 24000 g + 991 g = 24991 g, 25009 g +24991 g 500,000 g The smaller unit as 1 gram is equal to 1,000 milligrams, So 500,000 g = 500,000 X 1000 = 500,000,000 milligrams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement twenty five kilograms and 9 grams plus twenty four kilograms nine hundred and ninety one grams is equal to five lakhs grams or five hundred milligrams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-4

Explanation: Given 27 kg 650 g – 20 kg 990 g = As 27 kg 650 g = 27 X 1000 g + 650 g = 27000 g + 650 g = 27650 g, 20 kg 990 g = 20 X 1000 g + 990 g = 20000 g + 990 g = 20990 g, 27650 g -20990 g 6,660 g The smaller unit as 1 gram is equal to 1,000 milligrams, So 6,660 g = 6,660 X 1000 = 6,660,000 milligrams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement Twenty seven kilogram six hundred fifty grams minus  twenty kilogram nine hundred ninety grams is equal to six kilogram six sixty grams or six thousand six hundred sixty grams or sixty six lakhs sixty thousand milligrams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-5

Explanation: Given 14 kg 505 g – 4288 g = As 14 kg 505 g = 14 X 1000 g + 505 g = 14000 g + 505 g = 14505 g, 14505 g – 4288 g 10,217 g The mixed unit 10,217 grams is equal to 10 kg 217 grams, as 10217 g = 10217 ÷ 1000 kg = 10 kg 217 grams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement fourteen kilograms five hundred and five minus four thousand and two hundred eighty eight equals to ten kilograms two hundred and seventeen grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-6

Explanation: Given 5 kg 658 g + 57481 g = As 5 kg 658 g = 5 X 1000 g + 658 g = 5000 g + 658 g = 5658 g, 5658 g +57481 g 63,139 g The mixed unit 63,139 grams is equal to 63 kg 139 grams, as 63139 g = 631390 ÷ 1000 kg = 63 kg 139 grams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement five kilograms six hundred fifty eight grams plus fifty seven four hundred eighty one grams is equal to sixty three kilograms and one hundred thirty nine grams.

Eureka Math Grade 4 Module 2 Lesson 2 Problem Set Answer Key 1

Explanation: Given one package weighs 2 kilograms 485 grams. Another package weighs 5 kilograms 959 grams. The total weight of the two packages is 2 kilograms 485 grams + 5 kilograms 959 grams = 2 X 1000 + 485 = 2000 + 485 = 2485 g 5 X 1000 + 959 = 5000 + 959 = 5959 g 2485 g 5959 g 8,444 g 8,444 g = 8,444 ÷ 1000 = 8 kilograms 444 grams , Therefore, the total two packages weight is 8,444 grams or 8 kilograms 444 grams.

Question 5. Together, a pineapple and a watermelon weigh 6 kilograms 230 grams. If the pineapple weighs 1 kilogram 255 grams, how much does the watermelon weigh?

Answer: The watermelon weigh’s 4975 grams or 4 kilograms 975 grams,

Explanation: Given together, a pineapple and a watermelon weigh 6 kilograms 230 grams. If the pineapple weighs 1 kilogram 255 grams, so the watermelon weigh’s 6 kilograms 230 grams – 1 kilogram 255 grams = 6 kilograms 230 grams = 6 X 1000 g + 230 g = 6230 g, 1 kilogram 255 grams = 1 X 1000 g + 255 g = 1255 g, Now 6230 g – 1255 g = 6230 g -1255 g 4975 g Therefore, The watermelon weigh’s 4975 grams or 4975 g = 4975 ÷ 1000 = 4 kilograms 975 grams.

Question 6. Javier’s dog weighs 3,902 grams more than Bradley’s dog. Bradley’s dog weighs 24 kilograms 175 grams. How much does Javier’s dog weigh?

Answer: Javier’s dog weigh’s 28,077 grams or 28 kilograms 77 grams,

Explanation: Given Javier’s dog weighs 3,902 grams more than Bradley’s dog. Bradley’s dog weighs 24 kilograms 175 grams. So Javier’s dog weigh’s 24 kg 175 g + 3902 g = 24 kg 175g = 24 X 1000 g + 175 g = 24175 g Now 24175 g + 3902 g = 24175 g +3902 g 28077 g Therefore, Javier’s dog weigh’s 28,077 grams or 28,077 ÷ 1000 = 28 kilograms 77 grams.

Question 7. The table to the right shows the weight of three Grade 4 students. How much heavier is Isabel than the lightest student?

Answer: 5762 g or 5 kg 762 g heavier is Isabel than the lightest student Sue,

Explanation: Given the weight of three Grade 4 students, From it Isabel weight is 35 kg and the lightest student is Sue 29,238 g, So heavier is Isabel than the lightest student is 35 kg – 29,238 g = 35 X 1000 g – 29,238 g = 35,000 g – 29,238 g = 35,000 g 29,238 g 5,762 g 5,762 g = 5762 ÷ 1000 = 5 kilogram 762 g, Therefore, 5762 g or 5 kg 762 g heavier is Isabel than the lightest student Sue.

Eureka Math Grade 4 Module 2 Lesson 2 Exit Ticket Answer Key

Question 1. Convert the measurements. a. 21 kg 415 g = _21,415_ g b. 2 kg 91 g = __2,091__ g c. 87 kg 17 g = ___87,017_ g d. _96_ kg _20__ g = 96,020 g

Use a tape diagram to model the following problem. Solve using a simplifying strategy or an algorithm and write your answer as a statement.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-7

Explanation: Given to convert 21 kg 415 g, as 1 kg = 10 3 g= 1000 g so 21 kg 415 g = 21 X 1000 g + 415 g = 21000 g + 415 g = 21415 g, Used a tape diagram to model the following problem, Solved using a simplifying strategy and wrote my answer as a statement twenty one kilograms 415 grams is equal to twenty one thousand four hundred fifteen grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-8

Explanation: Given to convert 2 kg 91 g, as 1 kg = 10 3 g= 1000 g so 2 kg 91 g = 2 X 1000 g + 91 g = 2000 g + 91 g = 2091 g, Used a tape diagram to model the following problem, Solved using a simplifying strategy and wrote my answer as a statement two kilograms 91 grams is equal to two thousand ninety one grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-9

Explanation: Given to convert 87 kg 17 g, as 1 kg = 10 3 g= 1000 g so 87 kg 17 g = 87 X 1000 g + 17 g = 87000 g + 17 g = 87,017 g, Used a tape diagram to model the following problem, Solved using a simplifying strategy and wrote my answer as a statement eighty seven kilograms 17 grams is equal to eighty seven thousand and seventeen grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-10

Explanation: Given to convert 96,020 g, as 1 g = 1 ÷ 10 3 kg so 96,020 g = 96000 ÷ 1000 g + 20 g = 96 kg + 20 g = 96,020 g, Used a tape diagram to model the following problem, Solved using a simplifying strategy and wrote my answer as a statement ninety six kilograms twenty grams is equal to ninety six thousand and twenty grams.

Question 2. The table to the right shows the weight of three dogs. How much more does the Great Dane weigh than the Chihuahua?

Answer: The Great Dane weigh’s 57 kg 671 g or 57,671 g more than the Chihuahua,

Explanation: Given the table to the right shows the weight of three dogs. More the Great Dane weigh than the Chihuahua is 59 kg -1,329 g = 59 X 1000 g = 59000 g – 1329 g = 57,671 g or 57,671 g ÷ 1000 = 57 kg 671 g, Therefore, the Great Dane weigh’s 57 kg 671 g or 57,671 g more than the Chihuahua.

Eureka Math Grade 4 Module 2 Lesson 2 Homework Answer Key

6 kg = 6,000 g as 6 kg = 6 X 10 3 g = 6 X 1000g = 6,000 g.

8 kg = 8,000 g as 8 kg = 8 X 10 3 g = 8 X 1000 = 8,000 g.

15000 g = 15,000 kg ÷ 10 3 g = 15 kg, So 15 kg = 15,000 g.

24 kg = 24,000 g as 24 kg = 24 X 10 3 g = 24 X 1000 g = 24,000 g

550 kg = 550,000 g as 550 kg = 550 X 10 3 g = 550 X 1000 g = 550,000 g.

Question 2. Convert the measurements. a. 2 kg 700 g = ____2,700_______ g b. 5 kg 945 g = ______5,945_____ g c. 29 kg 58 g = ______29,058____ g d. 31 kg 3 g = _____31,003________ g e. 66,597 g = __66___ kg __597_____ g f. 270 kg 41 g = _____270,041_______ g

a. 2 kg 700 g = 1500 g

Explanation: 2 kg 700 g  as 1 kg = 10 3 g= 1000 g, 2 X 1000 g + 700 g = 2700 g.

b. 5 kg 945 g = 5945 g,

Explanation: 5 kg 945 g  as 1 kg = 10 3 g= 1000 g, 5 X 1000 g + 945 g= 5000 g + 945 g= 5945 g.

c. 29 kg 58 g = 29,058 g,

Explanation: 29 kg 58 g  as 1 kg = 10 3 g= 1000 g, 29 X 1000 g + 84 g = 29000 g + 58 g = 29,058 g.

d. 31 kg 3 g = 31,003 g,

Explanation: 31 kg 3 g  as 1 kg = 10 3 g= 1000 g, 31 X 1000 g + 3 g = 31000 g + 3 g = 31,003 g.

e. 66,597 g= 66 kg 597 g,

Explanation: As 1000 g = 1 kg, So 66,597 g =66,597 kg ÷ 1000 g = 66 kg 597 g.

f. 270 kg 41 g = 270,041 g

Explanation: 270 kg 41 g  as 1 kg = 10 3 g= 1000 g, 270 X 1000 g + 41 g = 270000 g + 41 g = 270,041 g.

Question 3. Solve. a. 370 g + 80 g b. 5 kg – 730 g c. Express the answer in the smaller unit: 27 kg 547 g + 694 g d. Express the answer in the smaller unit: 16 kg + 2,800 g e. Express the answer in mixed units: 4 kg 229 g – 355 g f. Express the answer in mixed units: 70 kg 101 g – 17 kg 862 g

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-11

Explanation: Given  370 g + 80 g = 370 g +80 g 450  g Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement three hundred seventy grams plus eighty grams is equal to four hundred fifty grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-12

Explanation: Given  5 kg – 730 g = As 5 kg = 5 X 1000 g = 5000 g, 5000 g – 730 g 4,270 g Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement five kilograms minus seven hundred thirty grams is equal to four thousand two hundred seventy grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-13

Explanation: Given  27 kg 547 g + 694 g = As 27 kg 547 g = 27 X 1000 g + 547 g = 27000 g + 547 g = 27,547 g, 27547 g +694 g 28,241 g The smaller unit as 1 gram is equal to 1,000 milligrams, So 28,241 g = 28,241 X 1000 = 28,241,000 milligrams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement twenty seven kilogram fifty seven grams plus six hundred ninety four is equal to twenty eight kilograms two hundred forty one grams or twenty eight hundred two lakh forty one thousand milligrams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-14

Explanation: Given 16 kg + 2800 g  = As 16 kg = 16 X 1000 g = 16000 g = 16,000 g, 16000 g +2800 g 18,800 g The smaller unit as 1 gram is equal to 1,000 milligrams, So 18,800 g = 18,800 X 1000 = 18,800,000 milligrams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement sixteen kilogram plus two thousand eight hundred grams twenty kilogram nine hundred ninety grams is equal to eighteen kilogram eight hundred grams or eighteen thousand eight hundred grams or eighteen hundred eight lakh milligrams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-15

Explanation: Given 4 kg 229 g – 355 g = As 4 kg 229 g = 4 X 1000 g + 229  = 4000 g + 229 g = 4,229 g, 4229 g – 355 g 3,874 g The mixed unit 3,874 grams is equal to 3 kg 874 grams, as 3874 g = 3874 ÷ 1000 kg = 3 kg 874 grams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement four kilograms two hundred twenty nine minus three hundred fifty five grams equals to three kilograms eight hundred and seventy four grams.

Eureka Math Grade 4 Module 2 Lesson 2 Answer Key-16

Explanation: Given 70 kg 101 g – 17 kg 862 g = 70 kg 101 g = 70 X 1000 g + 101 g = 70000 g + 101 g = 70,101 g, 17 kg 862 g = 17 X 1000 g + 862 g = 17000 g + 862 g = 17,862 g, 70101 g – 17862 g 52,239 g The mixed unit 52,239 grams is equal to 52 kg 239 grams, as 52,239 g = 52,239 ÷ 1000  = 52 kg 239 grams,  Used a tape diagram to model the problem. Solved using a simplifying strategy and wrote my answer as a statement seventy kilograms one hundred one gram minus seventeen kilograms eight hundred sixty two grams is equal to fifty two thousand two hundred thirty nine grams or fifty two kilograms two hundred thirty nine grams.

Question 4. One suitcase weighs 23 kilograms 696 grams. Another suitcase weighs 25 kilograms 528 grams. What is the total weight of the two suitcases?

Answer: The total weight of the two suitcases is 49 kilograms 224 grams or 49,224 grams,

Explanation: Given one suitcase weighs 23 kilograms 696 grams and another suitcase weighs 25 kilograms 528 grams. The total weight of the two suitcases is 23 kg 696 g + 25 kg + 528 g = As 1 Kg = 1000 g, so 23 kg 696 g = 23 X 1000 g + 696 g = 23,696 g and 25 kg 528 g = 25 X 1000 g + 528 g = 25,528 g, 23,696 g + 25,528 g 49,224 g or 49,224 g ÷ 1000  = 49 kg 224 g, So, The total weight of the two suitcases is 49 kilograms 224 grams or 49,224 grams.

Question 5. A bag of potatoes and a bag of onions combined weigh 11 kilograms 15 grams. If the bag of potatoes weighs 7 kilograms 300 grams, how much does the bag of onions weigh?

Answer: The bag of onions weigh’s 3,715 grams or 3 kilograms 715 grams,

Explanation: Given a bag of potatoes and a bag of onions combined weigh 11 kilograms 15 grams. If the bag of potatoes weighs 7 kilograms 300 grams, So the bag of onions weigh 11 kg 15 g – 7 kg 300 g = as 1 Kg = 1000 g, 11 kg 15 g = 11 X 1000 g + 15 g = 11,000 g + 15 g = 11,015 g and 7 kg 300 g = 7 X 1000 g + 300 g = 7000 g + 300 g = 7,300 g, Now 11,015 g -7,300 g 3,715 g or 3,715 g ÷ 1000  = 3 kg 715 g , Therefore, the bag of onions weigh’s 3,715 grams or 3 kilograms 715 grams.

Question 6. The table to the right shows the weight of three dogs. What is the difference in weight between the heaviest and lightest dog?

The difference in weight between the heaviest and lightest dog is 1,879 grams or 1 kilogram 879 grams,

Explanation: Given the table to the right shows the weight of three dogs. More the heaviest dog among three is Riley 23 kg 128 g weigh and the lightest dog among the three is Lassie 21 kg 249 g, So now the difference in weight between the heaviest and lightest dog is 23 kg 128 g – 21 kg 249 g = So 23 X 1000 g + 128 g = 23,128 g and 21 kg 249 g = 21 X 100 + 249 g = 21,249 g now 23,128 g -21,249 g 1,879 g or 1,879 ÷ 1000 = 1 kg 879 g, Therefore, the difference in weight between the heaviest and lightest dog is 1,879 grams or 1 kilogram 879 grams.

Eureka Math Grade 4 Module 2 Answer Key

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module 2 lesson 2 homework grade 4

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Grade 2 Module 4 Lesson 4 Homework

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1. GRADE HOME CONNECTIONS 2

2. teks/staar-based lessons, 3. nonproportional relationships module 4, 4. grade 5: module 4: unit 2: lesson 2 analyzing point of ..., 5. grade 4: module 4: unit 3: lesson 1 synthesizing ideas ..., 6. homework helper-grade 2 module 3, 7. grade 2 book of sprints, 8. for teachers nutrition lesson activities worksheets.

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COMMENTS

  1. Eureka Math Grade 4 Module 2 Lesson 2 Answer Key

    Eureka Math Grade 4 Module 2 Lesson 2 Exit Ticket Answer Key. Question 1. Convert the measurements. a. 21 kg 415 g = _21,415_ g b. 2 kg 91 g = __2,091__ g c. 87 kg 17 g = ___87,017_ g d. _96_ kg _20__ g = 96,020 g. Use a tape diagram to model the following problem. Solve using a simplifying strategy or an algorithm and write your answer as a ...

  2. Eureka Math Homework Time Grade 4 Module 4 Lesson 2

    It's Homework Time! Help for fourth graders with Eureka Math Module 4 Lesson 2.

  3. 4th Grade Math (Eureka Math/EngageNY)

    Unit 1: Module 1: Place value, rounding, and algorithms for addition and subtraction. 0/2000 Mastery points. Topic A: Place value of multi-digit whole numbers Topic B: Comparing multi-digit whole numbers Topic C: Rounding multi-digit whole numbers. Topic D: Multi-digit whole number addition Topic E: Multi-digit whole number subtraction.

  4. PDF Grade 4 Unit 2 Module 2 Practice Pages for Math at Home

    n 4 + 6 = 10 n 6 × 4 = 24 n 42 - 4 = 20 n 6 × 6 = 36 Key: 1 Chair: 1 Table: 2 There were 24 kids at Josie's party (including her), and each of them ate 3 pieces of

  5. Course: G4M2: Unit Conversions and Problem Solving with Metric Measurement

    Grade 4 Module 2 Collapse all Expand all. Unit Conversions and Problem Solving with Metric Measurement ... Homework Solutions Page. Promethean Flipchart Page. Google Slides Page. ... Lesson 4. Lesson 5. End-of-Module Reivew. Gr4Mod3. Gr4Mod4. Gr4Mod5. Gr4Mod6. Gr4Mod7. General Information. Kindergarten. Grade 1. Grade 2. Grade 3. Grade 5. Grade 6.

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    A 4th grade resource for teachers using Eureka Math and EngageNY. G4M4: Angle Measure and Plane Figures. A 4th grade resource for teachers using Eureka Math and EngageNY. G4M5: Fraction Equivalence, Ordering, and Operations. A 4th grade resource for teachers using Eureka Math and EngageNY. G4M6: Decimal Fractions.

  7. Printed Materials

    As the creator of Engage NY Math and Eureka Math, Great Minds is the only place where you can get print editions of the PK-12 curriculum.Our printed materials are available in two configurations: Learn, Practice, Succeed, or student workbooks, teacher editions, assessment and fluency materials. The Learn, Practice, Succeed configuration is available for grades K-8 and offers teachers ...

  8. PDF Grade 4, Module 4 Student File A

    10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 4, Module 4 Student File_A Contains copy-ready classwork and homework as well as templates (including cut outs) ... 42 HomeworkLesson 4 2. Use your right angle template to identify acute, obtuse, and right angles within this painting.

  9. Eureka Math Grade 2, Module 3, Lesson 4 Instructional Video

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