lesson 9 homework answer key grade 5

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Go Math! 5 Student Edition, Grade: 5 Publisher: Houghton Mifflin Harcourt

Go math 5 student edition, title : go math 5 student edition, publisher : houghton mifflin harcourt, isbn : 547352042, isbn-13 : 9780547352046, use the table below to find videos, mobile apps, worksheets and lessons that supplement go math 5 student edition., textbook resources.

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Math Expressions Grade 5 Unit 5 Lesson 9 Answer Key Division Practice

Solve the questions in Math Expressions Grade 5 Homework and Remembering Answer Key Unit 5 Lesson 9 Answer Key Division Practice to attempt the exam with higher confidence. https://mathexpressionsanswerkey.com/math-expressions-grade-5-unit-5-lesson-9-answer-key/

Math Expressions Common Core Grade 5 Unit 5 Lesson 9 Answer Key Division Practice

Math Expressions Grade 5 Unit 5 Lesson 9 Homework

Unit 5 Lesson 9 Division Practice Math Expressions Question 1.

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 350  ÷ 7

Set up the problem with the long division bracket. Put the dividend inside the bracket and the divisor on the outside to the left.

Put 350, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 7, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 35 by the divisor, 7.

35 divided by 7 is 5, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 7 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 35 ÷ 0.7 = 50

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 2400  ÷ 6

Put 2400, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 6, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first three numbers of the dividend, 240 by the divisor, 6.

240 divided by 6 is 4, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 6 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 24 ÷ 0.06 = 400

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 6.4  ÷ 8

Put 6.4, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 8, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first  numbers of the dividend, 6.4 by the divisor, 8.

6.4 divided by 8 is 0.8, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 6 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 6.4 ÷ 0.8 = 0.8

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 1800  ÷ 3

Put 1800, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 3, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first three numbers of the dividend, 180 by the divisor, 3.

180 divided by 3 is 60, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 6 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 18 ÷ 0.03 = 600

Put 33, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 3, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first  numbers of the dividend, 33 by the divisor, 3.

33 divided by 3 is 11, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 3 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 33 ÷ 3 = 11

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 6500  ÷ 5

Put 6500, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 5, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 65 by the divisor, 5.

65 divided by 5 is 1, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 1 so you have 15. 15 divided by 5 is 3, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 0.65 ÷ 0.05 = 13

Put 72, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 12, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first  numbers of the dividend, 72 by the divisor, 12.

72 divided by 12 is 6, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 12 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 72 ÷ 12 = 6

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 1156  ÷4

Put 1156, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 4, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 11 by the divisor, 4.

11 divided by 4 is 2, with a remainder of 3. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 3 so you have 5. 35 divided by 4 is 8, with a remainder of 3. Bring down the next number of the dividend and insert it after the 3 so you have 6. 36 divided by 4 is 9, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 11.56 ÷ 0.04 = 289

Put 216, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 8, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 21 by the divisor, 8.

21 divided by 8 is 2, with a remainder of 5. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 5 so you have 56. 56 divided by 8 is 7, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 216 ÷ 8 = 27

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 4904  ÷ 8

Put 4904, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 8, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 49 by the divisor, 8.

49 divided by 8 is 6, with a remainder of 1. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 1 so you have 10 10 divided by 8 is 1, with a remainder of 2. Bring down the next number of the dividend and insert it after the 2 so you have 4. 24 divided by 8 is 3, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 490.4 ÷ 0.8 = 613

Put 2380, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 28, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first three numbers of the dividend, 224 by the divisor, 28.

224 divided by 28 is 8, with a remainder of 14. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 14 so you have 140. 140 divided by 28 is 5, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 2380 ÷ 28 = 85

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 5148  ÷ 33

Put 5148, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 33, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 51 by the divisor, 33.

51 divided by 33 is 1, with a remainder of 18. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 18 so you have 184. 184 divided by 33 is 5, with a remainder of 19. Bring down the next number of the dividend and insert it after the 19 so you have 198. 198 divided by 33 is 6, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 5.148 ÷ 0.033 = 156

Solve. Explain how you know your answer is reasonable.

Question 13. Georgia works as a florist. She has 93 roses to arrange in vases. Each vase holds 6 roses. How many roses will Georgia have left over? Answer:  Georgia will be left with 15.5 roses.

Put 93, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 6, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first  numbers of the dividend, 9 by the divisor, 6.

9 divided by 6 is 1, with a remainder of 3. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 3 so you have 33. 33 divided by 6 is 5, with a remainder of 3. Bring down the next number of the dividend and insert it after the 3 so you have 30. 30 divided by 6 is 5, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 93 ÷ 6 = 15.5

Totally, Georgia will be left with 15.5 roses.

Question 14. Julia is jarring peaches. She has 25.5 cups of peaches. Each jar holds 3 cups. How many jars will Julia need to hold all the peaches? Answer: Julia will need 8.5 jars to  hold the peaches.

Put 25.5, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 3, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 25 by the divisor, 3.

25 divided by 3 is 8, with a remainder of 1. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 1 so you have 15. 15 divided by 3 is 5, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 25.5 ÷ 3 = 8.5

Thus, Julia will need 8.5 jars to  hold the peaches.

Question 15. The area of a room is 114 square feet. The length of the room is 9.5 feet. What is the width of the room? Answer: The width of the room is 12 feet.

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 1140  ÷ 95

Put 1140, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 95, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 114 by the divisor, 95.

114 divided by 9.5 is 95, with a remainder of 1. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 19 so you have 190. 190 divided by 95 is 2, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 114 ÷ 9.5 = 12

Thus, The width of the room is 12 feet.

Math Expressions Grade 5 Unit 5 Lesson 9 Remembering

Add or Subtract.

Explanation: By simplifying the given fractions, 1\(\frac{1}{2}\) = \(\frac{2 + 1}{2}\) = \(\frac{3}{2}\) \(\frac{3}{2}\)  can be written as 1.5 5\(\frac{5}{6}\) = \(\frac{30 + 5}{6}\) = \(\frac{35}{6}\) \(\frac{35}{6}\)  can be written as 15.83 Now add both the decimal numbers Then, 1.5 + 5.83 = 7.33.

Explanation: By simplifying the given fractions, 2\(\frac{2}{5}\) = \(\frac{10 + 3}{5}\) = \(\frac{13}{5}\) \(\frac{13}{5}\)  can be written as 2.6 5\(\frac{3}{10}\) = \(\frac{50 + 3}{10}\) = \(\frac{53}{10}\) \(\frac{53}{10}\)  can be written as 5.3 Now add both the decimal numbers Then, 2.6 + 5.3 = 7.9.

Explanation: By simplifying the given fractions, 1\(\frac{1}{3}\) = \(\frac{3 + 1}{3}\) = \(\frac{4}{3}\) \(\frac{4}{3}\)  can be written as 1.33 \(\frac{1}{6}\)  can be written as 0.16 Now substract both the decimal numbers Then, 1.33 – 0.16 = 1.17.

Explanation: By simplifying the given fractions, 7\(\frac{3}{10}\) = \(\frac{70 + 3}{10}\) = \(\frac{73}{10}\) \(\frac{73}{10}\)  can be written as 7.3 2\(\frac{1}{5}\) = \(\frac{10 + 1}{5}\) = \(\frac{11}{5}\) \(\frac{11}{5}\)  can be written as 2.2 Now add both the decimal numbers Then, 7.3 + 2.2 = 9.5.

Explanation: By simplifying the given fractions, 9\(\frac{1}{8}\) = \(\frac{72 + 1}{8}\) = \(\frac{73}{8}\) \(\frac{73}{8}\)  can be written as 9.125 2\(\frac{3}{4}\) = \(\frac{8 + 3}{4}\) = \(\frac{11}{4}\) \(\frac{11}{4}\)  can be written as 2.75 Now substract both the decimal numbers Then, 9.125 – 2.75 = 6.375.

Explanation: By simplifying the given fractions, 5\(\frac{2}{3}\) = \(\frac{15 + 2}{3}\) = \(\frac{17}{3}\) \(\frac{17}{3}\)  can be written as 5.66 Now substract both the numbers Then, 12 – 5.66 = 6.34.

Find each product.

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 640  ÷ 8

Put 640, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 8, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 64 by the divisor, 8.

64 divided by 8 is 8, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 0. 0 divided by 8 is 0, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 6.4 ÷ 0.08 = 80

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 72  ÷ 8

Put 72, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 8, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first  numbers of the dividend, 72 by the divisor, 8.

72 divided by 8 is 9, with a remainder of 0. You can ignore the remainder for now. Since the remainder is 0, your long division is done.

So, 7.2 ÷ 0.8 = 9

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 567  ÷ 7

Put 567, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 7, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 56 by the divisor, 7.

56 divided by 7 is 8, with a remainder of 0. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 0 so you have 07. 7 divided by 7 is 1, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 5.67 ÷ 0.07 = 81

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 533.6  ÷ 58

Put 533.6, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 58, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first three numbers of the dividend, 533 by the divisor, 58.

533 divided by 58 is 9, with a remainder of 11. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 11 so you have 116. 116 divided by 58 is 2, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 5.336 ÷ 0.58 = 9.2

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 63  ÷ 9

Put 63, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 9, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first three numbers of the dividend, 63 by the divisor, 9.

63 divided by 9 is 7, with a remainder of 0. You can ignore the remainder for now. Since the remainder is 0, your long division is done.

So, 6.3 ÷ 0.9 = 7

If the divisor is a decimal number, move the decimal all the way to the right. Count the number of places and move the decimal in the dividend the same number of places. Add zeroes if needed. Then we have 175  ÷ 5

Put 175, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 5, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 17 by the divisor, 5.

17 divided by 5 is 3, with a remainder of 2. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 2 so you have 25. 25 divided by 5 is 5, with a remainder of 0. Since the remainder is 0, your long division is done.

So, 1.75 ÷ 0.05 = 35

Question 19. Stretch Your Thinking Write a real world division problem for which you would drop the remainder. Answer: Alex and joy have 147 awesome unicorn stickers, if they can only fir 13 stickers on each page of their sticker book, How many pages will be full of stickers?

Put 147, the dividend, on the inside of the bracket. The dividend is the number you’re dividing. Put 13, the divisor, on the outside of the bracket. The divisor is the number you’re dividing by. Divide the first two numbers of the dividend, 14 by the divisor, 13.

14 divided by 13 is 1, with a remainder of 1. You can ignore the remainder for now. Bring down the next number of the dividend and insert it after the 1 so you have 17. 17 divided by 13 is 1, with a remainder of 4. Bring down the next number of the dividend and insert it after the 4 so you have 40. 40 divided by 13 is 3, with a remainder of  10. Since the remainder is 10, your long division is done.

So, 147 ÷ 13 = 11.3.

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Texas Go Math Grade 5 Lesson 9.1 Answer Key Formulas for Area and Perimeter

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 9.1 Answer Key Formulas for Area and Perimeter.

Unlock the Problem

A formula is an equation that expresses a mathematical rule. You can use formulas to find the perimeter and area of rectangles.

Lloyd is planting a rectangular garden that measures 40 feet by 24 feet. He wants to put a fence around it to protect his vegetables from rabbits. How many feet of fencing does he need?

Use a formula to find the perimeter. P = l + w + l + w, P = perimeter; l = length; w = width P = 40 + ___24____ + __40_____ + ___24____ Replace the unknowns with the lengths and the widths. P = ___128____ Add. The perimeter is ___128____ feet. So, Lloyd needs ___128____ feet of fencing.

Remember Area is measured in square units, such as square feet or sq ft. Answer: The perimeter is 128 feet, So Lloyd needs 128 feet of fencing,

Explanation: Lloyd is planting a rectangular garden that measures 40 feet by 24 feet. He wants to put a fence around it to protect his vegetables from rabbits. So number of feet of fencing does he need is using a formula to find the perimeter P = l + w + l + w, P = perimeter; l = length; w = width is P= 40 + 24 + 40 + 24 = 128 feet, So Lloyd needs 128 feet of fencing.

Lloyd needs to find how large his garden is so he can order enough mulch for the garden. What is the area of Lloyd’s garden?

Use a formula to find the area. A = l × w, A = area; I = length; w = width A = ____40____ × __24_____ Replace the unknowns with the length and the width. A = ____960_______ Multiply. So, the area of Lloyd’s garden is _____960___ square feet. Answer: The area of the garden is 960 square feet,

Explanation: Given Lloyd is planting a rectangular garden that measures length 40 feet by width 24 feet, therefore the area of Lloyd’s garden is 40 X 24 = 960 square feet.

You can also use the formula P = 2l + 2w to find the perimeter. What is the perimeter of a rectangle that is 12 feet long and 16 feet wide? P = 2 × ____12_____ + 2 × ___16_______ Replace the unknowns with the length and the width. P = __24 + 32_______ The perimeter is ___56___ feet. Answer: The perimeter is 56 feet,

Explanation: Given to find the perimeter of a rectangle that is 12 feet long and 16 feet wide, by using the formula p = 2l + 2w, so p = 2 X 12 + 2 X 16, p = 24 + 32, p = 56 feet. therefore the perimeter is 56 feet.

Math Talk Mathematical Processes

Explain how you can use the properties of operations to write P = l + w + l + w as P = 2l + 2w. Answer: By using properties of operations addition we write p = l + w + l + w as P = 2l + 2w,

Explanation: Given to write p = l + w + l + w by using properties of operations addition we add common terms l with l and w with w we get p = (l + l) + (w + w), p = 2l + 2 w.

STEP 1: Separate the figure into a rectangle and a square.

STEP 2: Find the area of the rectangle. A = l × w A = __3 X 3_________ A = ___9________ The area of the rectangle is _____9______ square meters.

STEP 3: Find the area of the square. A = ___5 X 4________ A = ____20_______ A = ___________ The area of the square is _____20______ square meters.

STEP 4: Find the area of the complex figure by adding the areas. A = ____9_______ + ___20________ A = ____29_______ So, the area of the complex figure is ____29_______ square meters. Answer: The area of the complex figure is 29 square meters,

Explanation: STEP 1: Separate the figure into a rectangle and a square, STEP 2: Finding the area of the rectangle as A = l × w, A = 3 X 3, A = 9, The area of the rectangle is 9 square meters, STEP 3: Finding the area of the square A = 5 X 4, A = 20, The area of the square is 20 square meters.

STEP 4: Find the area of the complex figure by adding the areas. A = 9 + 20, A = 29, So, the area of the complex figure is 29 square meters.

Share and Show

Explanation: Given the side of the square is 14 meters, therefore the perimeter of a square is 14 + 14 + 14 + 14 = 56 meters.

Problem Solving

Question 3. H.O.T. Explain how you can use s to write the formula for the perimeter of a square with side length s. Answer: Perimeter= 4s,

Explanation: Given s to write the formula for the perimeter of a square with side length s is s + s + s + s =  4s.

Question 4. H.O.T. A rectangle has an area of 96 square feet. If the length of the rectangle is 12 feet, what is the width of the rectangle? Answer: 8 feet is the width of the rectangle,

Explanation: Given a rectangle has an area of 96 square feet. If the length l of the rectangle is 12 feet, let w be the width of the rectangle as we know area of rectangle is A = l X w substituting 96 square feet= 12 feet X w, w = 96 square feet  ÷ 12 feet = 8 feet.

Question 5. Brent plans to stain a deck that is 14 feet by 8 feet. If one can of stain covers an area of 100 square feet, how many cans of stain will he need? Explain. Answer: 2 cans of stain Brent need,

Explanation: Brent plans to stain a deck that is 14 feet by 8 feet. If one can of stain covers an area of 100 square feet, So a deck is of area 14 feet X 8 feet = 112 square feet  as one can of stain covers an area of 100 square feet therefore  number of cans of stain Brent will need is 2.

Explanation: Latoya uses 50 feet of wood to make a rectangular garden bed, So number of feet of fencing does he need is using a formula for finding the perimeter P = l + w + l + w, P = perimeter; l = length; w = width is 50 = 10 + w + 10 + w upon solving we get 2w = 50 – 20 = 30, 2 w = 30 therefore w = 30 ÷ 2 = 15 feet.

Explanation: Given Maggie wants to fence off two side-by-side sections of her garden and each section is 14 feet long and 6 feet wide, She says she needs 80 feet of fencing, but wrong with her thinking, as if we see 80 feet(14 + 6 + 14 + 6) will cover only one section off the garden fence for two side-by-side sections of her garden she needs 2 X 80 feet = 160 feet.

Daily Assessment Task

Fill in the bubble for the correct answer choice.

Question 8. Apply Tina is fixing a rectangular sign. She plans to place metal trim around the sign edges. The rectangle measures 32 inches by 9 inches. How much trim will Tina need? (A) 36 inches (B) 41 inches (C) 72 inches (D) 82 inches Answer: (D) 82 inches,

Explanation: Given Tina is fixing a rectangular sign. She plans to place metal trim around the sign edges. The rectangle measures 32 inches by 9 inches. So trim will Tina need is 32 inches + 9 inches + 32 inches + 9 inches = 82 inches which matches with (D).

Question 9. A rectangle has a length of 5 meters and a width of 4 meters. Which equation can you use to find the perimeter? (A) P = 4 × 5 (B) P = 4 × 4 (C) P = 4 + 4 + 5 + 5 (D) P = 4 + 5 Answer: (C) P = 4 + 4 + 5 + 5,

Explanation: Given rectangle has a length of 5 meters and a width of 4 meters we know perimeter P = l + w + l + w, where P = perimeter; l = length; w = width so we get the equation to find the perimeter is P = 4 + 4 + 5 + 5 which matches with (C).

5th Grade Math Formulas for Area and Perimeter Lesson 9.1 Answer Key Question 10. Multi-Step Lana had an “L” shaped piece of felt. Her mom cut it into two rectangles. One rectangle measured 4 inches by 9 inches, and the other measured 4 inches by 3 inches. What is the total area of the two rectangles? (A) 40 square inches (B) 48 square inches (C) 72 square inches (D) 24 square inches Answer: (B) 48 square inches,

Explanation: Given Lana had an “L” shaped piece of felt. Her mom cut it into two rectangles. One rectangle measured 4 inches by 9 inches, and the other measured 4 inches by 3 inches. So area of one rectangle is 4 inches X 9 inches = 36 square inches, other area of rectangle is 4 inches X 3 inches = 12 square inches, so the total area of the two rectangles is 36 square inches + 12 square inches = 48 square inches which matches with (B).

TEXAS Test Prep

Question 11. Mai wants to tile the floor of her kitchen. Each tile has an area of 1 square foot. The floor of her kitchen is 11 feet by 16 feet. How many tiles does she need? (A) 150 (B) 54 (C) 176 (D) 352 Answer: (C) 176,

Explanation: Given Mai wants to tile the floor of her kitchen. Each tile has an area of 1 square foot. The floor of her kitchen is 11 feet by 16 feet. So total area of Mai kitchen is 11 feet X 16 feet = 176 square foot matches with (c).

Texas Go Math Grade 5 Lesson 9.1 Homework and Practice Answer Key

Explanation: Given rectangle has a length of 21 feet and a width of 15 feet we know perimeter P = l + w + l + w, where P = perimeter; l = length; w = width so the perimeter of rectangle is P = 21 + 15 + 21 + 15 = 72 feet.

Explanation: Given the side of the square is 17 inches, the area of square is 17 inches X 17 inches = 289 square inches.

Question 3. A rectangle has a perimeter of 68 inches. 1f the width of the rectangle is 10 inches, what is the length of the rectangle? Explain how you know. Answer: The length of the rectangle is 24 inches,

Explanation: Given a rectangle that has a perimeter of 68  inches. If the width of the rectangle is 10 inches, let l be the length of the rectangle as we know perimeter P = l + w + l + w, where P = perimeter; l = length; w = width so the length of rectangle l is 68 = 10 + 10 + l + l, so 2l = 68 – 20 = 48, l = 48 ÷ 2 = 24 inches.

Question 4. A square has an area of 81 square feet. What is the length of each side of the square? Explain how you know. Answer: The length of side of the square is 9 feet,

Explanation: Given a square has an area of 81 square feet. The length of each side of the square will be as area of square is s X s , so 81 square feet = s X s, s X s = 9 feet X 9 feet , therefore s = 9 feet.

Question 5. Lea wants to put a fence around her garden. Her garden measures 14 feet by 15 feet. She has 50 feet of fencing. How many more feet of fencing does Lea need to put a fence around her garden? Answer:

Go Math Grade 5 Lesson 9.1 Formulas of Area and Perimeter Question 6. Lea wants to put a new layer of soil on her 14 feet by 15 feet garden. She finds the area of her garden so she knows how much soil to buy. If one bag of soil covers 20 square feet, how many bags of soil will Lea need? Explain. Answer: 11 bags of soil Lea needs,

Explanation: Given Lea wants to put a new layer of soil on her 14 feet by 15 feet garden. She finds the area of her garden as 14 feet X 15 feet = 210 square feet, she knows how much soil to buy If one bag of soil covers 20 square feet, 210 square feet requires 210 ÷ 20 = 10 bags remainder 10 square feet, therefore 11 bags of soil Lea needs.

Lesson Check

Fill in the bubble completely to show your answer.

Question 7. A soccer field has a length of 100 yards and a width of 60 yards. Which equation can you use to find the area of the soccer field? (A) A = 100 × 60 (B) A = 100 + 60 + 100 + 60 (C) A = 100 + 60 (D) A = 160 × 4 Answer: (A) A = 100 × 60,

Explanation: Given a soccer field has a length of 100 yards and a width of 60 yards, as we know area of square is Area is equal to length X width so the equation for the area of the soccer field is A = 100 X 60 which matches with (A).

Question 8. A baseball diamond is a square with a perimeter of 360 feet. What is the length of one side? (A) 80 feet (B) 180 feet (C) 90 feet (D) 60 feet Answer: (C) 90 feet,

Explanation: Given a baseball diamond is a square with a perimeter of 360 feet. So the length of one side will be as perimeter of square with side s is p = 4s so 360 feet = 4 X s, therefore one side is 360 ÷ 4 = 90 feet matches with (C).

Question 9. Zoey wants to cover her bedroom floor with carpet squares. Each square has an area of 1 square foot. Her bedroom measures 12 feet by 14 feet. How many carpet squares does Zoey need? (A) 168 (B) 144 (C) 336 (D) 52 Answer: (A) 168,

Explanation: Given Zoey wants to cover her bedroom floor with carpet squares. Each square has an area of 1 square foot. Her bedroom measures 12 feet by 14 feet. So number of squares does Zoey need is 12 X 14 = 168 square feet matches with (A).

Go Math Homework Lesson 9.1 Area and Perimeter Answer Key Question 10. Edward wants to put a string of lights around a rectangular window that is 32 inches wide and 40 inches high. How long will the string of lights need to be to go around the window? (A) 72 inches (B) 1,280 inches (C) 144 inches (D) 112 inches Answer: (B) 1,280 inches,

Explanation: Given Edward wants to put a string of lights around a rectangular window that is 32 inches wide and 40 inches high. The string of lights need to be to go around the window is 32 X 40 = 1,280 inches matches with (B) 1,280 inches.

Question 11. Multi-Step Chantal buys two small rugs for her kitchen. One rug measures 3 feet by 5 feet. The other rug measures 4 feet by 6 feet. What is the area of the part of the kitchen the two rugs will cover? (A) 39 square feet (B) 30 square feet (C) 24 square feet (D) 36 square feet Answer: (A) 39 square feet,

Explanation: Given Chantal buys two small rugs for her kitchen. One rug measures 3 feet by 5 feet. The other rug measures 4 feet by 6 feet. First rug covers 3 feet by 5feet is 5 X 3 = 15 square feet, Other rug covers 4 feet by 6 feet is 4 X 6 = 24 square feet, The area of the part of the kitchen the two rugs will cover is 15 square feet + 24 square feet = 39 square feet.

Area and Perimeter 5th Grade Lesson 9.1 Homework Answer Key Question 12. Multi-Step Isaac is painting a wall that is 9 feet by 18 feet. So far, he has painted a part of the wall that is a 4 feet by 7 feet rectangle. What is the area of the part of the wall that Isaac has left to paint? (A) 190 square feet (B) 134 square feet (C) 22 square feet (D) 151 square feet Answer: (B) 134 square feet,

Explanation: Given Isaac is painting a wall that is 9 feet by 18 feet. So far, he has painted a part of the wall that is a 4 feet by 7 feet rectangle. Total area of the wall is 9 feet X 18 feet = 162 square feet, Part of the wall painted is 4 feet by 7 feet = 28 square feet, The area of the part of the wall that Isaac has left to paint is 162 square feet – 28 square feet = 134 square feet matches with (B).

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Eureka Math Grade 4 Module 5 Lesson 9 Answer Key

Fractions are the important topics in maths. This will be helpful in the real-time environment. Know-how and where to apply the formulas from this page. Get a detailed explanation for all the questions here. Download Eureka Math Answers Grade 4 chapter 9 pdf for free of cost. As per your convenience, we have provided the solutions in pdf format so that you can prepare offline.

Engage NY Eureka Math 4th Grade Module 5 Lesson 9 Answer Key

Get the guided notes for chapter 9 Answer Key from here. This will be the best resource to enhance your math skills. The topics covered in this chapter are Fractional units. test yourself by solving questions given at the end of the chapter.

Eureka Math Grade 4 Module 5 Lesson 9 Problem Set Answer Key

Each rectangle represents 1.

Answer: 2/4 = 1/2.

Explanation: In the above-given question, given that, compose the shaded fractions into larger fractional units. Express the equivalent fractions in a number sentence using division. 2/2 = 1. 4/2 = 2. 2/4 = 1/2.

Answer: 3/6 = 1/2.

Answer: 5/10 = 1/2.

Answer: 4/8 = 1/2.

Answer: 2/6 = 1/3.

Answer: 2/8 = 1/4.

Answer: 2/10 = 1/5.

Answer: 2/12 = 1/6.

e. What happened to the size of the fractional units when you composed the fraction?

Answer: The size of the fractional units is increased.

Explanation: In the above-given question, given that, whenever the size of the fractional units decreases when we decompose the fraction. decomposing = dividing. whenever the size of the fractional units increases when we compose the fraction. composing = adding.

f. What happened to the total number of units in the whole when you composed the fraction?

Answer: The total number of units in the whole is increased when we composed the fraction.

Explanation: In the above-given question, given that, the total number of units in the whole is increased when we composed the fraction.

Explanation: In the above-given question, given that, compose the shaded fractions into larger fractional units. Express the equivalent fractions in a number sentence using division. 2/2 = 1. 6/2 = 3. 2/6 = 1/3.

Answer: 3/9 = 1/3.

b. Express the equivalent fractions in a number sentence using division.

Explanation: In the above-given question, given that, compose the shaded fractions into larger fractional units. Express the equivalent fractions in a number sentence using division. 2/2 = 1. 8/2 = 4. 2/8 = 1/4.

Answer: 3/12 = 1/4.

Eureka Math Grade 4 Module 5 Lesson 9 Exit Ticket Answer Key

Answer: 4/12 = 1/3.

Eureka Math Grade 4 Module 5 Lesson 9 Homework Answer Key

Answer: 6/12 = 1/2.

Answer: 7/14 = 1/2.

Explanation: In the above-given question, given that, compose the shaded fractions into larger fractional units. Express the equivalent fractions in a number sentence using division. 2/2 = 1. 10/2 = 5. 2/10 = 1/5.

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